Draw an infinite tree according to the following rules:
- Each tree node is labeled 1 or 2, and has a number of children equal to its label.
- If the nodes are placed into their breadth-first search ordering, then two consecutive nodes have the same label if and only if they have the same parent.
There are two choices for the root label, but the trees they produce are almost the same as each other, so let's say the root is labeled 2, giving the tree shown below together with its spiraling breadth first search order. (If the root were labeled 1, the only difference would be to add one more node labeled 1 above the node that is the root in the drawing.)
Then the breadth-first sequence of labels that we obtain is exactly the Kolakoski sequence, starting from its third term. The Kolakoski sequence begins 1,2,2,1,1,2,1,2,2,1,2,2... and has the property that it equals the sequence of run-lengths in itself: the numbers 1, 2, 2, etc. are exactly the numbers of consecutive 1's, 2's, 1's, etc. in the sequence. Our tree is defined in such a way that each run of consecutive equal labels comes from the same parent, so the run-lengths of the sequence equal the numbers of children of the nodes, which equal the labels of the nodes, which define the sequence itself.( Read more...Collapse )
ETA: See next post for an alternative algorithm that avoids the recursion.